KS3Solutions
Geometry and measures
Answers grouped by subtopic.
Perimeter and area
- GM-Q1AnswerFind the area of a rectangle 8 cm by 5 cm.Working
- Area = length × width = 8 × 5 = 40 cm2.
Answer: 40 cm2 - GM-Q2AnswerFind the perimeter of a rectangle 9 cm by 4 cm.Working
- Perimeter = 2 × (9 + 4) = 2 × 13 = 26 cm.
Answer: 26 cm - GM-Q3AnswerFind the area of a triangle with base 10 cm and height 6 cm.Working
- Area = 0.5 × base × height = 0.5 × 10 × 6 = 30 cm2.
Answer: 30 cm2
Volume
- GM-Q4AnswerFind the volume of a cuboid 6 cm by 4 cm by 3 cm.Working
- Volume = length × width × height = 6 × 4 × 3 = 72 cm3.
Answer: 72 cm3 - GM-Q5AnswerA cylinder has radius 2 cm and height 5 cm. Find the volume. Use pi = 3.14.Working
- Area of base = π × r2 = 3.14 × 22 = 3.14 × 4 = 12.56 cm2.
- Volume = base area × height = 12.56 × 5 = 62.8 cm3.
Answer: 62.8 cm3
Angles and properties
- GM-Q6AnswerTwo angles in a triangle are 45 degrees and 65 degrees. Find the third angle.Working
- Angles in a triangle sum to 180 degrees.
- Third angle = 180 - (45 + 65) = 180 - 110 = 70 degrees.
Answer: 70 degrees - GM-Q7AnswerOn a straight line, one angle is 110 degrees. Find the other angle.Working
- Angles on a straight line sum to 180 degrees.
- Other angle = 180 - 110 = 70 degrees.
Answer: 70 degrees
Pythagoras
- GM-Q9AnswerA right triangle has two shorter sides 6 cm and 8 cm. Find the hypotenuse.Working
- Use Pythagoras: c2 = 62 + 82 = 36 + 64 = 100.
- c = 10 cm.
Answer: 10 cm - GM-Q10AnswerA right triangle has hypotenuse 13 cm and one side 5 cm. Find the remaining side.Working
- Use Pythagoras: other2 = 132 - 52 = 169 - 25 = 144.
- other = 12 cm.
Answer: 12 cm
Transformations
- GM-Q11AnswerReflect the point (3, -2) in the 𝑥-axis. Give the new coordinates.Working
- Reflection in the 𝑥-axis keeps 𝑥 the same and changes the sign of 𝑦.
Answer: (3, 2) - GM-Q12AnswerRotate the point (2, 1) 90 degrees clockwise about the origin. Give the new coordinates.Working
- A 90 degree clockwise rotation uses (𝑥, 𝑦) -> (𝑦, -𝑥).
- So (2, 1) becomes (1, -2).
Answer: (1, -2)